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Select the equivalent conductivity of `1.0 M H_(2)SO_(4)`, if its conductivity is `0.26 ohm^(-1) cm^(-1)`: |
Answer» Correct Answer - `130 ohm^(-1)cm^(2)(g eq.)^(-1)` Conductivity or specific conductance (k)`=26xx10^(-2)" ohm^(-1) cm^(-1)` Molarity of `H_(2)SO_(4)` solution (M)=1M Normality of `H_(2)SO_(4)` solution (N)`=1xx2=2N " " (because H_(2)SO_(4) "is a disbasic acid")` `Lambda_(E)=(kxx1000)/(N)=((26xx10^(-2)" ohm"^(-1)cm^(-1))xx1000cm^(3))/((2.0"g eq")^(-1))=130" ohm"^(-1)cm^(2)("g eq")^(-1)`. |
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