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Separation between two bodies each of mass 1 kg is 10 cm. Find the force ofGravitation between them r = 10 cm = 10^(-1) m. |
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Answer» SOLUTION :` implies F = (Gm_(1) m_(2))/r^2 = ((6.67 xx10^(-11))(1) (1))/(10^(-1))^(2)` `F = 6.67 xx10^(-9) N` |
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