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Seven grams of nitrogen is mixed with 12 g of oxygen in a tube and then sealed. Calculate the velocity of sound through the tube at `27^@C`. |
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Answer» `c=sqrt((gammaRT)/(M))` Since nitrogen and oxygen are both diatomic, `gamma=1.4` `(m_1+m_2)/(M)=(m_1)/(M_1)+(m_2)/(M_2)` `implies(7+12)/(M)=(7)/(28)+(12)/(32)` `impliesM=30.4` `c=sqrt((1.4xx8.3xx300)/(30.4xx10^-3))=338.6(m)/(s)` |
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