Shabana bought 16 dozen ball bens and sold them at a loss equal to S.P

1.	Shabana bought 16 dozen ball bens and sold them at a loss equal to S.P. of 8 ball pens. Find(i) her loss percent(ii) S.P. of 1 dozen ball pens, if she purchased these 16 dozen ball pens for Rs 576.
Answer» Given, number of ball pens bought by Shabana is = 16 dozen = 16×12 = 192 pens So, let’s consider the cost price of each pen as Rs x CP of 8 pens = Rs 8x Let SP of one pen be = Rs x So, SP of 192 pens = 192x Given, loss of 192 pens = SP of 8 ball pens So, loss = 8SP 192x = (192+8) SP SP = 192x/200 Loss = CP – SP = x – 192x/200 (i) Loss% = (loss/CP) × 100 = (x – 192x/200)/x × 100 = (200x-192x)/200x × 100 = 8/2 = 4% (ii) Given, CP of 16 dozen pens = Rs 576 192x = 576 x = 576/192 We know that SP of 1 pen = 192x/200 SP of dozen pens = 12 × 192x/200 = 12 × 192/200 × 576/192 = 12 × 576/200 = 34.56 ∴ Loss% = 4% and SP of 1 dozen pens is Rs 34.56

Shabana bought 16 dozen ball bens and sold them at a loss equal to S.P. of 8 ball pens. Find(i) her loss percent(ii) S.P. of 1 dozen ball pens, if she purchased these 16 dozen ball pens for Rs 576.

Answer»

Given, number of ball pens bought by Shabana is = 16 dozen = 16×12 = 192 pens

So, let’s consider the cost price of each pen as Rs x

CP of 8 pens = Rs 8x

Let SP of one pen be = Rs x

So, SP of 192 pens = 192x

Given, loss of 192 pens = SP of 8 ball pens

So, loss = 8SP

192x = (192+8) SP

SP = 192x/200

Loss = CP – SP

= x – 192x/200

(i) Loss% = (loss/CP) × 100

= (x – 192x/200)/x × 100

= (200x-192x)/200x × 100

= 8/2

= 4%

(ii) Given, CP of 16 dozen pens = Rs 576

192x = 576

x = 576/192

We know that SP of 1 pen = 192x/200

SP of dozen pens = 12 × 192x/200

= 12 × 192/200 × 576/192

= 12 × 576/200

= 34.56

∴ Loss% = 4% and SP of 1 dozen pens is Rs 34.56

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