1.

Shade the feasible region for the inequations 2x+3yle6,xge0,yge0 in a rough figure.

Answer»

SOLUTION :Let US consider `2x+3y=6` Clearly `2xx0+3xx0=0le6`. `thereforeO(0,0)` satisfies `2x+3yle6andxge0,YGE0` is the first quadrant. THUS the shaded REGION is the feasible region.


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