1.

Shape of `Fe(CO)_(5)` isA. octahedralB. square planarC. trigonal bipyramidalD. square bipyramidal

Answer» Correct Answer - C
In `[Fe(CO)_(5)]` the oxidation number of Fe is zero `Fe^(0) (3d^(6) 4d^(2))` Since CO is a strong field ligand, the electron configuration is resuffled so as to provide one vacant d orbital for `dsp^(3)` hybrization leaging to trigonal bipyramidal geometry as well as shape.


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