SHO of periodic time 2 second starts its oscillation from the lower end of its path of motion, its phase will be……….at time 2 second.

SHO of periodic time 2 second starts its oscillation from the lower en

1.	SHO of periodic time 2 second starts its oscillation from the lower end of its path of motion, its phase will be……….at time 2 second.
Answer» Solution :`implies THETA= (2pi t)/(T)+PHI = (2pi)/(2)xx2+ (3PI)/(2)` `=2pi + (3pi)/(2) = (7pi)/(2) rad`.