Shortest wavelengths in balmer series of Li2+

1.	Shortest wavelengths in balmer series of Li2+
Answer» Answer: The shortest WAVELENGTH of the light EMITTED is when the electron jumps from Infinity to 3. For Li²⁺, λ = 9/R × 3² m. = 81/R m. This is the Required Answer. Explanation: HOPE that HELPS you

Answer»

Answer:

The shortest WAVELENGTH of the light EMITTED is when the electron jumps from Infinity to 3. For Li²⁺, λ = 9/R × 3² m. = 81/R m. This is the Required Answer.

Explanation:

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Shortest wavelengths in balmer series of Li2+