1.

Show that ""^(10)C_2+^(11)C_2+^(12)C_2+^(13)C_2+...+^(20)C_2=^(21)C_3-^(10)C_3.

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Answer : `""^(10)C_2+^(11)C_2+^(12)C_2+^(13)C_2+...+^(20)C_2=^(21)C_3-^(10)C_3`.


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