Show that 28n cannot end with digit 0 for any natural number

1.	Show that 28n cannot end with digit 0 for any natural number
Answer» Solution: If any number ends with the digit 0, it should be divisible by 10 or in other words, it will also be divisible by 2 and 5 as 10 = 2 × 5 It can be observed that 5 is not in the prime factorisation of (2²x7)ⁿor 28ⁿ. Hence, for any value of n, 28ⁿ will not be divisible by 5. Therefore, 28ⁿ cannot end with the digit 0 for any natural number n.

Answer»

Solution:

If any number ends with the digit 0, it should be divisible by 10 or in other words, it will also be divisible by 2 and 5 as 10 = 2 × 5
It can be observed that 5 is not in the prime factorisation of (2²x7)ⁿor 28ⁿ.
Hence, for any value of n, 28ⁿ will not be divisible by 5.
Therefore, 28ⁿ cannot end with the digit 0 for any natural number n.

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Show that 28n cannot end with digit 0 for any natural number

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