1.

Show that [[a_1,b_1,-c_1],[-a_2,b_2,c_2],[a_3,b_3,-c_3]]= [[a_1,b_1,c_1],[a_2,b_2,c_2],[a_3,b_3,c_3]]

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SOLUTION :`[[a_1,b_1,-c_1],[-a_2,-b_2,c_2],[a_3,b_3,-c_3]]=[[a_1,b_1,-c_1],[a_2,b_2,-c_2],[a_3,b_3,-c_3]](-1)`
(TALING COMMON (-1) from `R_2`)
`(-)(-)[[a_1,b_1,c_1],[a_2,b_2,c_2],[a_3,b_3,c_3]]=[[a_1,b_1,c_1],[a_2,b_2,c_2],[a_3,b_3,c_3]]`
(TAKING common (-1) from `C_3`)


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