Show that : (a+1b)m×(a−1b)n(b+1a)m×(b−1a)n=(ab)m+n

1.	Show that : (a+1b)m×(a−1b)n(b+1a)m×(b−1a)n=(ab)m+n
Answer» Show that : $\frac{{(a + \frac{1}{b})}^{m} \times {(a - \frac{1}{b})}^{n}}{{(b + \frac{1}{a})}^{m} \times {(b - \frac{1}{a})}^{n}} = {(\frac{a}{b})}^{m + n}$

Answer»

Show that :

$\frac{{(a + \frac{1}{b})}^{m} \times {(a - \frac{1}{b})}^{n}}{{(b + \frac{1}{a})}^{m} \times {(b - \frac{1}{a})}^{n}} = {(\frac{a}{b})}^{m + n}$

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