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Show that a median of a triangle divides it whose triangles of equal area

Answer» Let ABC be a triangle and Let AD be one of its medians.In △ABD and △ADC the vertex is common and these bases BD and DC are equal.Draw AE⊥BC.Now area(△ABD)= 21\u200b ×base×altitude of△ADB= 21\u200b ×BD×AE= 21\u200b ×DC×AE(∵BD=DC)but DC and AE is the base and altitude of △ACD= 21\u200b × base DC × altitude of △ACD=area△ACD⇒area(△ABD)=area(△ACD)Hence the median of a triangle divides it into two triangles of equal areas. solution.


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