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Show that any positive odd integer is of the form 6q + 1, or 6q + 3 or 6q + 5, where q is some integer. |
Answer» Let a is a positive odd integer and apply Euclid’s division algorithm a = 6q + r, Where 0 ≤ r < 6 for 0 ≤ r < 6 probable remainders are 0, 1, 2, 3, 4 and 5. a = 6q + 0 or a = 6q + 1 or a = 6q + 2 or a = 6q + 3 or a = 6q + 4 or a = 6q + 5 may be form Where q is quotient and a = odd integer. This cannot be in the form of 6q, 6q + 2, 6q + 4. [all divides by 2] Hence, any positive odd integer is of the form 6q + 1, or 6q + 3 or (6q + 5) |
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