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Show that B (–3, 3√3) ,C(–3, –3√3) are the points on this circle |
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Answer» Distance of B from origin \(\sqrt{(-3-0)^2+(3\sqrt{3}-0)^2}\) = \(\sqrt{(-3)^2+(-3\sqrt{3})^2}\) = \(\sqrt{9+27}\) = \(\sqrt{36}\) = 6 Distance of C from origin = \(\sqrt{(-3)^2+(-3\sqrt{3})^2}\) = \(\sqrt{9+27}\) = \(\sqrt{36}\) = 6 B(–3, 3√3) and C(–3, –3√3) are on the circle. |
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