Show that each diagonal of a parallelogram divide it into two congruent triangles. The following are the steps involved in showing the above result. Arrange them in sequential order. A) In `triangleABC` and `triangleCDA`, AB=DC and BC=AD `(therefore` opposite angles of parallelogram) AC=AC (common side). B) Let ABCD be a parallelogram. Join AC. C) By SSS congruence property, `triangleABC ~=triangleCDA`. D) Similarly, BD divides the triangle into two congruent triangles.A. BACDB. BDACC. BADCD. BDCA

Show that each diagonal of a parallelogram divide it into two congruen

1.	Show that each diagonal of a parallelogram divide it into two congruent triangles. The following are the steps involved in showing the above result. Arrange them in sequential order. A) In `triangleABC` and `triangleCDA`, AB=DC and BC=AD `(therefore` opposite angles of parallelogram) AC=AC (common side). B) Let ABCD be a parallelogram. Join AC. C) By SSS congruence property, `triangleABC ~=triangleCDA`. D) Similarly, BD divides the triangle into two congruent triangles.A. BACDB. BDACC. BADCD. BDCA
Answer» Correct Answer - A BACD is the required sequential order.