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Show that f(x) = tan x is an increasing function on (–π/2, π/2). |
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Answer» Given as f(x) = tan x f'(x) = (d/dx)(tan x) ⇒ f’(x) = sec2x As given x ∈ (–π/2, π/2). That is 4th quadrant, where ⇒ sec2x > 0 ⇒ f’(x) > 0 Thus, condition for f(x) to be increasing Hence, f(x) is increasing on interval (–π/2, π/2). |
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