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Show that for no value of k, the equation 5x²+kx-4=0 has real and equal roots |
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Answer» -Quadratic equation 5x²+kx-4 = 0To Show:-For no REAL value of k, the equation 5x²+kx-4=0 has real and equal roots .SOLUTION:- ☀We are given quadratic equation is 5x²+kx-4 = 0On comparing, we GET :-a = 5B = kc = -4 ☀We know that, If a quadratic equation ax²+bx+c = 0 has equal and real roots then the discriminant.Hence,here is no real value of k ,the equation 5x²+kx-4 = 0 has real and equal roots. Showed..! ⠀⠀⠀⠀¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ |
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