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| 1. |
Show that for same range of projectile there can be two angles of throw. |
| Answer» When any object is thrown with α angle and other with 90-α then the range will be same. So we can say that for same range of projectile there can be two angles.Let projectile angle α=90-α Then, R = u.usin2α/g R\'=u.usin2(90-α)/g R\'=u.usin(180-2α)/g R\'=u.usin2α/gIt means R=R\' | |