1.

Show that:(i) ∛(729)/ ∛ (1000) = ∛(729/1000)(ii) ∛(-512)/ ∛ (343) = ∛(-512/343)

Answer»

(i) ∛(729)/ ∛(1000) = ∛(729/1000)

L.H.S=  ∛(729)/ ∛(1000)

∛(729)/ ∛(1000) = ∛(9×9×9)/ ∛(10×10×10)

= ∛(93/103)

= 9/10

 R.H.S =  ∛(729/1000)

∛(729/1000) = ∛(9×9×9/10×10×10)

= ∛ (93/103)

= 9/10

 L.H.S = R.H.S

(ii) ∛(-512)/ ∛(343) = ∛(-512/343)

L.H.S =  ∛(-512)/ ∛ (343)

∛(-512)/ ∛(343) = ∛-(8×8×8)/ ∛(7×7×7)

= ∛-(83/73)

= -8/7

 R.H.S = ∛(-512/343)

∛(-512/343) =∛-(8×8×8/7×7×7)

= ∛-(83/73)

= -8/7

L.H.S = R.H.S



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