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Show that, if sum of the digits of a three-digit number is subtracted from the same numberwe always get a number divisible by 9. |
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Answer» three digit no. be=100x+10y+zsum of the digits of a 3 digit no.= x+y+zresulting no.= 100x+10y+z-(x+y+z)= 99x+9y so it is divisible by 9 |
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