Saved Bookmarks
| 1. |
Show that is the half life period of a first order reaction is independent of then initial concentration of the reactant. |
|
Answer» For first order reaction, equation of rate constant is K = \(\frac{2.303}{t}\) log \(\frac{a}{a-x}\) Where a = initial concentration of reactant When half of the reaction is completed, x = \(\frac{a}{2}\) a - x = a - \(\frac{a}{2}\) = \(\frac{a}{2}\) putting t = t1/2 in the equation, we get k = 2.303/ t1/2 \(\Big(\frac{a}{a/2}\Big)\) = 2.303/ t1/2 log 2 = 0.693/k This shows half-life is independent from initial concentration of reactant |
|