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Show that \( \log _{25}^{10}=\frac{1}{2} \times \log _{5} 10 \). |
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Answer» Log2510 = \(\frac {1}{log_{10}25} = \frac {1}{log_{10}5^2} = \frac {1}{2log_{10}5}\) = \(\frac {log_510}{2}\) (∵ logab = \(\frac {1}{log_ba}\)) Hence proved |
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