1.

Show that \( \log _{25}^{10}=\frac{1}{2} \times \log _{5} 10 \).

Answer»

Log2510 = \(\frac {1}{log_{10}25} = \frac {1}{log_{10}5^2} = \frac {1}{2log_{10}5}\)

\(\frac {log_510}{2}\) (∵ logab = \(\frac {1}{log_ba}\))

Hence proved



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