1.

Show that moment of inertia of a solid body of any shape change eith temperature as I=I_0(1+2 alhatheta). Where I_0 is the moment of inertia at 0^C nad alpha is the coefficient of liear expansion of the solid.

Answer»

SOLUTION :Given, `I_0= moment of inertia at 0^@C`
` alpha= Coefficient of inertia `
expansion
` To prove I=I_0 (1+2 alpha theta)
Let the temperature changes to `theta` from `0^@C`
`Delta T= theta`
` Let R_0 be the radius of gyration `
` Now R_0=R(1+ alpha theta)`
`I_0=MR^2 where M is the MASS. `
` Now I=MR^2=MR^2 ((1+alpha theta)^2)`
` [by binominal expansion and neglecting
alpha_2 theta_2 which is a very SMALL VALUE]`
`=MR^2(1+2 alpha theta)`
` So,I=I_0(1+2 alpha theta).........(proved).`


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