1.

Show that none of the operation given in the above question has identity.

Answer»

An element e  Q will be the identity element for the operation if

a*e = a = e*a, a  Q

(i) a*b = a − b

If a*e = a,a ≠ 0  a −e = a, a ≠ 0  e = 0

Also, e*a = a  e − a = a  e = 2a

⇒ e = 0 = 2a,a ≠ 0

But the identiry is unique. Hence this operation has no identity.

(ii) a*b = a2 + b2

If a*e = a, then a2 + e2 = a

For a = −2, (−2)2 + e2 = 4 + e2 ≠ −2

Hence, there is no identity element.

(iii) a*b = a + ab

If a*e = a  a + ae = a  ae = 0  e = 0,a ≠ 0

Also if e*a = a  e + ea = a  e = a/(1 - a), a ≠ 1

∴ e = 0 = a/(1 - a), a ≠ 0

But the identity is unique. Hence this operation has no identify.

(iv) a*b = (a − b)2

If a*e = a, then (a − e)2 = a. A square is always positive, so for

a = −2,(−2 − e)2 ≠ − 2

Hence, there is no identity element.

(v) a*b = ab/4

If a*e = a, then ae /4 = a. 

Hence, e = 4 is the identity element.

∴  a*4 =4 *a = 4a/4 = a

(vi) a*b = ab2

If a*e =a then ae2 = a ⇒ e2 = 1 ⇒ e = ± 1

But identity is unique. Hence this operation has no identity.

Therefore only part (v) has an identity element.



Discussion

No Comment Found