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Show that none of the operation given in the above question has identity. |
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Answer» An element e ∈ Q will be the identity element for the operation if a*e = a = e*a, a ∈ Q (i) a*b = a − b If a*e = a,a ≠ 0 ⇒ a −e = a, a ≠ 0 ⇒ e = 0 Also, e*a = a ⇒ e − a = a ⇒ e = 2a ⇒ e = 0 = 2a,a ≠ 0 But the identiry is unique. Hence this operation has no identity. (ii) a*b = a2 + b2 If a*e = a, then a2 + e2 = a For a = −2, (−2)2 + e2 = 4 + e2 ≠ −2 Hence, there is no identity element. (iii) a*b = a + ab If a*e = a ⇒ a + ae = a ⇒ ae = 0 ⇒ e = 0,a ≠ 0 Also if e*a = a ⇒ e + ea = a ⇒ e = a/(1 - a), a ≠ 1 ∴ e = 0 = a/(1 - a), a ≠ 0 But the identity is unique. Hence this operation has no identify. (iv) a*b = (a − b)2 If a*e = a, then (a − e)2 = a. A square is always positive, so for a = −2,(−2 − e)2 ≠ − 2 Hence, there is no identity element. (v) a*b = ab/4 If a*e = a, then ae /4 = a. Hence, e = 4 is the identity element. ∴ a*4 =4 *a = 4a/4 = a (vi) a*b = ab2 If a*e =a then ae2 = a ⇒ e2 = 1 ⇒ e = ± 1 But identity is unique. Hence this operation has no identity. Therefore only part (v) has an identity element. |
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