. Show that p(x) = x3– 3x2+ 2x – 6 has only one real zero. 3.

1.	. Show that p(x) = x3– 3x2+ 2x – 6 has only one real zero. 3.
Answer» Let the number of persons be\xa0x. Then,x−496\u200b−x96\u200b=4⇔x−41\u200b−x1\u200b=964\u200b⇔x(x−4)x−(x−4)\u200b=241\u200b ⇔x2−4x−96=0⇔(x−12)(x+8)=0⇔x=12So, required number\xa0=x−4=8. 어험가쩌쏘 떷텊초 추흐ㅛ허모

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