Show that (sinθ -cosθ + 1) / ( sinθ + cosθ - 1) = 1 /(secθ - tanθ )

Show that (sinθ -cosθ + 1) / ( sinθ + cosθ - 1) = 1 /(secθ - tan�

1.	Show that (sinθ -cosθ + 1) / ( sinθ + cosθ - 1) = 1 /(secθ - tanθ )
Answer» Answer : (sinθ -cosθ + 1) / ( sinθ + cosθ - 1) = 1 /(secθ - tanθ ) We can use the trigonometric identity (sec²θ = 1 + tan²θ)