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Show that terminal velocity of a sphere falling through a viscous medium is proportional to the square of its radius. |
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Answer» Solution :A SPHERICAL object of volume density. The apparent weight of the solid = VISCOUS drag force. Hence the object begins to move with a STEADY speed CALLED terminal speed. `6pietaav=4/3 PIA^(3) (rho-sigma)g"here"rho gt sigma` `therefore v=(2a^(2)g)/(9eta) (rho-sigma)` "Hence" v alpha a^(2)` |
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