1.

Show that terminal velocity of a sphere falling through a viscous medium is proportional to the square of its radius.

Answer»

Solution :A SPHERICAL object of volume density. The apparent weight of the solid = VISCOUS drag force. Hence the object begins to move with a STEADY speed CALLED terminal speed.
`6pietaav=4/3 PIA^(3) (rho-sigma)g"here"rho gt sigma`
`therefore v=(2a^(2)g)/(9eta) (rho-sigma)`
"Hence" v alpha a^(2)`


Discussion

No Comment Found