Saved Bookmarks
| 1. |
Show that the circumference of the Bohr orbit for the hydrogen atom is an intergral multiple of the de Broglie wavelength associated with the electron revolving around the orbit. |
|
Answer» Solution :According to Bohr.s THEORY, `mvr=(nh)/(2pi)`(n=1,2,3,…….so on) ` or 2pir=(nh)/(mv) or mv=(nh)/(2pir)`……..(i) According to de Broglie equation, `GAMMA=h/(mv) or mv=(h)/(gamma)`…………..(ii) COMPARING (i)and (ii), `(nh)/(2pir)=h/(pi)or 2pir=ngamma` THUS,the circumference`(2pir)`of the Bohr orbit for hydrogen ATOM is an into the de Broglie wavelength. |
|