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Show that the cirumference of the Bohr orbit for hydrogen atom is an integral multiple of the de Broglie wavelength associated with the electron moving around the orbit. |
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Answer» SOLUTION :According to Bohr POSTULATE of angular momentum, `mvr= n h/(2PI) or 2 pi r=n h/(mv)` ...(i) According to de Broglie equation, `lambda=h/(mv)` ...(ii) Substituting this VALUE in eqn. (i) we get `2 pi r= n lambda` Thus, the cirumference `(2pi r)` of the bohr orbit for hydrogen atom is an integral mutiple of de Broglie wavelength. |
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