Show that the data given below is in agreement with the law of constant composition {:("Exp. No.","Mass of iron","Mass of iron oxide"),("(i)","2.7812 g","3.9756 g"),("(ii)","3.0499 g","4.3596 g"),("(iii)","4.4913 g","6.4202 g"):}

Show that the data given below is in agreement with the law of constan

1.	Show that the data given below is in agreement with the law of constant composition {:("Exp. No.","Mass of iron","Mass of iron oxide"),("(i)","2.7812 g","3.9756 g"),("(ii)","3.0499 g","4.3596 g"),("(iii)","4.4913 g","6.4202 g"):}
Answer» Solution :Experiement No. (i) MASS of iron = 2.7812 g , Mass of iron oxide = 3.9756 g PERCENTAGE of iron `= ((2.7812g))/((3.9756g))xx100=70%` Percentage of oxygen `= 100 - 70 = 30 %` Experiment No. (ii) Mass of iron = 3.0499 , Mass of iron oxide = 4.3596 g Percentage of iron `= ((3.0499))/((4.3596g))xx100=70%` Percentage of oxygen `= 100-70=30%` Experiment No. (iii) Mass of iron = 4.4913 g , Mass iron oxide = 6.4202 g Percentage of iron `= ((4.4913g))/((6.42402g))xx100=70%` Percentage of oxygen `= 100 - 70 = 30 %` Since the RATIO by weights of iron and oxygen in the THREE oxides is the same, the DATA is according to Law of constant Composition.