InterviewSolution
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InterviewSolution
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Show that the equation `2(a^2+b^2)x^2+2(a+b)x+1=0` has no real roots when `a!=b` |
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Answer» The given equation is `2(a^(2)+b^(2))x^(2)+2(a+b)x+1=0.` `:." "D=4(a+b)^(2)-8(a^(2)+b^(2))` `=-4(a^(2)+b^(2)-2ab)=-4(a-b)^(2)lt0," when "a-bne0.` So, the given equation has no real roots, when `aneb.` |
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