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Show that the expression of the time period T of a simple pendulum of length l given by `T = 2pi sqrt((l)/(g))` is dimensionally correctA. RightB. WrongC. Information incompleteD. None of these |
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Answer» Correct Answer - A Give, `T=2pisqrt(l)/(g)` Dimensionally `[T]=sqrt(([L])/([LT^(-2)]))=[T]` As in the above equation, the dimensions of both side are same. Therefore, the given formula is dimensionally correct. |
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