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Show that the following planes are at right angles: vector r.(2i - j + k) = 15 and vector r.(i - j - 3k) = 3 |
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Answer» The normal vectors are vector n1 = vector(2i - j + k) and vector n2 = vector(i - j - 3k) vector(n1.n2) = (2)(1) + (-1)(-1) + (1)(-3) = 2 + 1 – 3 = 0 ⇒ vector(n1 ⊥r to n2), i.e., the normals to the planes are at right angles. So, the planes are at right angles. |
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