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Show that the horizontal vector and displacement vector in two dimensions . |
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Answer» SOLUTION :As horizontal range `=(u^(2) sin 2 THETA) /(G)` For `theta=45^(@), 2 theta =90^(@)` `THEREFORE` Horizontal range =`(u^(2) sin 90^(2))/(g)=(u^(2))/(g)` (MAXIMUM) |
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