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Show that the line`(x-1)/2=(y-2)/3=(z-3)/4a n d(x-4)/5=(y-1)/2`intersect. Find their point of intersection.A. (0,0,0)B. (1,1,1)C. (-1,-,1,-1)D. (1,2,3) |
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Answer» Correct Answer - C Given lines are `(x-1)/(2)=(y-2)/(3)=(z-3)/(4)=r["say"]......(i)` `and (x-4)/(5)=(y-1)/(2)=z.....(ii)` Any point on the line (i) is (2r+1, 3r+2, 4r+3) If they interest, then the point satisfies the second line we get `(2r+1-4)/(5)=(3r+2-1)/(2)=4r+3` `Rightarrow (2r-3)/(5)=(3r-1)/(2) Rightarrow r=-1` `therefore` Required point is [(2(-1)+1,3(-1)+2,4(-1)+3] `=(-2+1,-3+2,-4+3)` =(-1,-1,-1) |
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