Show that the magnitude of a vector is equal to the square root of the scalar product of the vector with itself .

Show that the magnitude of a vector is equal to the square root of the

1.	Show that the magnitude of a vector is equal to the square root of the scalar product of the vector with itself .
Answer» Solution :If `vec(A)"\|\|"vec (B)` then `theta = 0^(@)` ` :. vec(A) .vec(B) = AB cos theta = AB ` and `vec(A). Vec(A) = \|vec(A)"\|\|"vec(A)\| =A^(2)` ` :.\|vec(A)\|= sqrt(vec(A).vec(A))` hence the MAGNITUDE of a vector is equal to the SQUARE root of the scalar product of the vector with itself . MAGNITUDEOF vector is equal to the square root of the scalar product of the vector with itself .