InterviewSolution
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InterviewSolution
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Show that the normal component of electrostatic field has a discontinuity from one side of a charged surface to another given by (vecE_2 - vecE_1). Htan = sigma/(epsi_0) where hatn is a unit vector normal to the surface at a point and o is the surface charge density at that point. (The direction of în is from side 1 to side 2). Hence, show that just outside a conductor, the electric field is sigma/(epsi_0) hatn. |
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Answer» Solution : Consider a charged surface having surface CHARGE density o. Normal electric field is PRESENT oneither side of surface but directions of electric fields `vecE_1 and vecE_2`are mutually opposite as shown in Fig. Thus field has a DISCONTINUITY from one side of charged surface to ANOTHER, As `vecE_2 = SIGMA(2epsi_0)hatn and vecE_1 = (-sigma)/(2epsi_0).hatn` Thus, `(vecE_2 - vecE_1)hatn = sigma/epsi_0` This shows that the electric field just outside the conductor is ` sigma//epsi_0`. 
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