1.

Show that the pathprojectilemation is perabolic alsofind the expression for the time periodof projectile​

Answer»

Answer:

Let a body is projected with speed um/s inclined θ with horizontal line.

Then, vertical COMPONENT of u, u

y

=ucosθ

Horizontal component of u

X

=usinθ

acceleration on horizontal, ax=0

acceleration on vertical, ay=−g

Now, USE formula

X=u

x

t

X=ucosθ.t

t=X/ucosθ--------------------------(1)

Again, y=u

y

t+1/2a

y

t

2

y=usinθt−1/2gt

2

put equation (1) here,

y=usinθ×x/ucosθ−1/2gt

2

×x

2

/u

2

cos

2

θ

=tanθx−1/2gx

2

/u

2

cos

2

y=tanθ.x−1/2gx

2

/u

2

cos

2

θ

this equation is similar to standard equation of PARABOLA y=ax

2

+bx+c her, a,band c are constant

So, A projectile motion is parabolic motion.

solution


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