InterviewSolution
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Show that the points (0,-1),(-2,3),(6,7) and (8,3) are vertices of a rectangle. |
Answer» Solution : `THEREFORE absbar(AB) = sqrt((0 + 2)^2 + (-1-3)^2)` `sqrt(4+6) = sqrt(20)` `absbar(AB) = sqrt((-2-6)^2 + (3-7)^2)` `sqrt(64+16) = sqrt(80)` `absbar(CD) = sqrt((6-8)^2 + (7-3)^2)` `sqrt(4+16) = sqrt(20)` `absbar(AD) = sqrt((8-0)^2 + (3+1)^2)` = `sqrt(64+16) = sqrt(80)` `therefore` the opposite sides are EQUAL and two CONSECUTIVE sides are perpendicular So it is a rectangle. |
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