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Show that the points `(0,7,10),(-1,6,6) and (-4,9,6)` form a righat angled isosceles triangle. |
Answer» We have, `AB=sqrt((-1-0)^(2)+(6-7)^(2)+(6-10)^(2))=sqrt(18)=3sqrt(2)` `BC=sqrt((-4+1)^(2)+(9-6)^(2)+(6-6)^(2))=sqrt(18)=3sqrt(2)` `and AC=sqrt((-4-0)^(2)+(9-7)^(2)+(6-7)^(2))=sqrt(36)=6` Clearly, `AB= BC and AB^(2)+BC^(2)=(18+18)=36=AC^(2)` Hence, triangle ABC is an isosceles right-angled triangle. |
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