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Show that the product of three positive integers is divisible by 6. |
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Answer» Let n be any positive integer. Since any positive integer is of the form 6q or 6q + 1 or 6q + 2 or 6q + 3 or 6q + 4, 6q + 5. If n = 6q, n (n + 1) (n + 2) = 6q (6q + 1) (6q + 2), which is divisible by 6 If n = 6q + 1 n (n + 1) (n + 2) = (6q + 1) (6q + 2) (6q + 3) n (n + 1) (n + 2) = 6 (6q + 1) (3q + 1) (2q + 1) Which is divisible by 6 If n = 6q + 2 n (n + 1) (n + 2) = (6q + 2) (6q + 3) (6q + 4) n (n + 1) (n + 2) = 12 (3q + 1) (2q + 1) (2q + 3), Which is divisible by 6. Similarly we can prove others. Hence it is proved that the product of three consecutive positive integers is divisible by 6. |
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