1.

Show that the product of three positive integers is divisible by 6.

Answer»

Let n be any positive integer.

Since any positive integer is of the form 6q or 6q + 1 or 6q + 2 or 6q + 3 or 6q + 4, 6q + 5.

If n = 6q,

n (n + 1)   (n + 2)  = 6q (6q + 1)   (6q + 2), which is divisible by 6

If n = 6q + 1

n (n + 1)   (n + 2)  = (6q + 1)   (6q + 2)   (6q + 3)

n (n + 1)   (n + 2)  = 6 (6q + 1)   (3q + 1)   (2q + 1)  Which is divisible by 6

If n = 6q + 2

n (n + 1)   (n + 2)  = (6q + 2)   (6q + 3)   (6q + 4)

n (n + 1)   (n + 2)  = 12 (3q + 1)   (2q + 1)   (2q + 3),

Which is divisible by 6.

Similarly we can prove others.

Hence it is proved that the product of three consecutive positive integers is divisible by 6.



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