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Show that the relation R on R defined as `R= {(a,b): a |
Answer» `R = {(a,b): a le b}` If the relation is reflexive, then `(a,a) in R` Here, `a le a` `:. f(a,a)` is true. So, relation is reflexive. If the relation is symmetric, then if `(a,b) in R` then`(b,a) in R`. Here, if `a le b` then `b le a` For `a =2, b= 5`, `2 lt 5` and `5 gt 2` `:.` Relation is not symmetric. Let `(a,b) in R and (b,c) in R` `=> (a le b)` & `(b le c)`. `=> (a le c)` . `:. (a,c) in R`. `:. R` is transitive. |
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