1.

Show that the relation R on R defined as `R= {(a,b): a

Answer» `R = {(a,b): a le b}`
If the relation is reflexive,
then `(a,a) in R`
Here, `a le a`
`:. f(a,a)` is true.
So, relation is reflexive.

If the relation is symmetric,
then if `(a,b) in R` then`(b,a) in R`.
Here, if `a le b` then `b le a`
For `a =2, b= 5`,
`2 lt 5` and `5 gt 2`
`:.` Relation is not symmetric.

Let `(a,b) in R and (b,c) in R`
`=> (a le b)` &  `(b le c)`.
`=> (a le c)` .
`:. (a,c) in R`.
`:. R` is transitive.


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