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InterviewSolution
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Show that the rms velocity of `O_(2)` molecule is `sqrt(2)` times that of `SO_(2)`. Atomic weight of sulphur is 32 and atomic weight of oxygen is 16. |
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Answer» Correct Answer - `sqrt(2)C_(SO_2)` As rms velocity at a given temperature `prop 1/(sqrt(M))` `:. (C_(OXY))/(C_(SO_2)) = sqrt((M_(SO_2))/(M_(OXY))) = sqrt((32 + 2 xx 16)/(32)) = sqrt(2)` `C_(OXY)= sqrt(2)C_(SO_2)`. |
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