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Show that the roots of the equation x2 + px – q2 = 0 are real for all real values of p and q. |
Answer» x2 + px – q2 = 0 Compare given equation with the general form of quadratic equation, which is ax2 + bx + c = 0 a = 1, b = p, c = -q2 Using discriminant formula: D = b2 – 4ac = (p)2 – 4 x 1 x (-q2) = p2 + 4 q2 > 0 Hence roots are real for all real values of p and q. |
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