InterviewSolution
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InterviewSolution
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Show that the sequence defined by ` T_(n) = 3n+5` is an AP. Find the common difference . |
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Answer» We have ` T_(n) = 3n+5` Replacing n by ( n-1) in (i), we get ` T_(n-1)= 3( n-1) + 5 Rightarrow T_(n-1) = 3n+2` Subtacting (ii) from (i), we get ` ( T_(n) - T_(n-1) = ( 3n + 5) - ( 3n+2) =3`,which is constant Hence, the given sequence in an AP with common differnece 3. |
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