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Show that the sum of all odd integers between 1 and 1000 which are divisible by 3 is 83667. |
Answer» Here,first term =3 and last term=999. It is an ap-3,9,15,21.........Common difference =6999=3+(n-1)6996/6=n-1166+1=nn=167Now sum of terms is given by-Snth=n/2(2a+(n-1)d)167/2(2×3+166×6)167/2(1002)=83667L.H.S=R.H.SHence proved<br>?ᴅᴏɴᴛ ᴋɴᴏᴡ | |