Show that the sum of (m+n) th and (m-n) th terms of an AP is equal to twice the mth terms.

Show that the sum of (m+n) th and (m-n) th terms of an AP is equal to

1.	Show that the sum of (m+n) th and (m-n) th terms of an AP is equal to twice the mth terms.
Answer» Let the A.P be\xa0The first term is \'a\'The common difference is \'d\'.The nth term of the A.P is given by,\xa0The (m+n)th term of A.P is\xa0The (m-n)th term of A.P is\xa0The sum of (m+n)th and (m-n)th term of an A.P is given by,\xa0....(1)Now, m th term of A.P is given by,Twice of m th term is\xa0From (1),Therefore,\xa0The sum of (m+n)th and (m-n)th term of an A.P is equal to twice the mth term