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Show that the three points `-2hati+3hatj+5hatk, hati+2hatj+3hatk, 7hati-hatk` are collinear |
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Answer» Clearly,we have `vec(AB)` = (position vector of B) - (position vector of A) `= (hati + 2hatj + 3hatk) - (-2hati + 3hatj + 5hatk) = (3hati - hatj - 2hatk)` `vec(BC) =` (position vector of C) - (position vector of B) `= (7hati - 3hatk) - (hati + 2hatj +3hatk) =(6hati - 2hatj - 4hatk)` `:. vec(AB) = 2vec(BC)` , which shows that `vec(AB) ` and `vec(BC)` are parallel vectors, Hence the points A,B and C collinear. |
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