1.

Show that y=sin^(2)omegat does not represent simple harmonic but periodic. What is the period of the given function.

Answer»

Solution :Given, `y=sin^(2)omegat` or `y=(1)/(2)(1-cos 2omegat)`
Velocity of the particle `V=(DY)/(dx)=(1)/(2)[0+(sin2omegat)(2OMEGA)]`
`v=(omega)sin2omegat`
Particle ACCELERATION `a=(dv)/(dt)=2omega^(2)cos2omega t`
Hence `y=sin^(2)omegat` is periodic but does not execute S.H.M. Acceleration is not proportional to the displacement.


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